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4-1.Newton's Laws of Motion
easy
A body of mass $‘M’$ collides against a wall with a velocity $v$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)
A
$Zero$
B
$2Mv$
C
$Mv$
D
$-2\, Mv$
Solution
(d)Change in momentum$ = m{\vec v_2} – m{\vec v_1}$$ = – mv – mv = – 2mv$
Standard 11
Physics
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