Gujarati
4-1.Newton's Laws of Motion
easy

A body of mass $‘M’$ collides against a wall with a velocity $v$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)

A

$Zero$

B

$2Mv$

C

$Mv$

D

$-2\, Mv$

Solution

(d)Change in momentum$ = m{\vec v_2} – m{\vec v_1}$$ = – mv – mv = – 2mv$

Standard 11
Physics

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