4-1.Newton's Laws of Motion
medium

A women throws an object of mass $500\,g$ with a speed of $25\, ms^{-1}$.

$(a)$ What is the impulse imparted to the object ?

$(b)$ If the object hits a wall and rebounds with half the original speed, what is the change in momentum of the object ?

Option A
Option B
Option C
Option D

Solution

Mass of the object $(m)=500 \mathrm{~g}=0.5 \mathrm{~kg}$

Speed of the object $(v)=25 \mathrm{~m} / \mathrm{s}$

$(a)$ Impulse imparted to the object = change in momentum

$=m v-m u$

$=m(v-u)$

$=0.5(25-0)=12.5 \mathrm{~N} \mathrm{~s}$

$(b)$ Half of initial velocity is,

$\quad=-\frac{25}{2} \mathrm{~m} / \mathrm{s}$

$v^{\prime}=-12.5 \mathrm{~m} / \mathrm{s}$

$\therefore \text { Change in momentum } =m\left(v^{\prime}-v\right)$

$=0.5(-12.5-25)$

$=-18.75 \mathrm{~N} \mathrm{~s}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.