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4-1.Newton's Laws of Motion
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A women throws an object of mass $500\,g$ with a speed of $25\, ms^{-1}$.
$(a)$ What is the impulse imparted to the object ?
$(b)$ If the object hits a wall and rebounds with half the original speed, what is the change in momentum of the object ?
Option A
Option B
Option C
Option D
Solution
Mass of the object $(m)=500 \mathrm{~g}=0.5 \mathrm{~kg}$
Speed of the object $(v)=25 \mathrm{~m} / \mathrm{s}$
$(a)$ Impulse imparted to the object = change in momentum
$=m v-m u$
$=m(v-u)$
$=0.5(25-0)=12.5 \mathrm{~N} \mathrm{~s}$
$(b)$ Half of initial velocity is,
$\quad=-\frac{25}{2} \mathrm{~m} / \mathrm{s}$
$v^{\prime}=-12.5 \mathrm{~m} / \mathrm{s}$
$\therefore \text { Change in momentum } =m\left(v^{\prime}-v\right)$
$=0.5(-12.5-25)$
$=-18.75 \mathrm{~N} \mathrm{~s}$
Standard 11
Physics