A body of mass 10,kg is moving with an initial speed of 20,m / s . body stops after 5,s due to frict

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4-2.Friction

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A body of mass $10\,kg$ is moving with an initial speed of $20\,m / s$. The body stops after $5\,s$ due to friction between body and the floor. The value of the coefficient of friction is (Take acceleration due to gravity $g =10\; ms ^{-2}$)

A

$0.2$

B

$0.3$

C

$0.5$

D

$0.4$

(JEE MAIN-2023)

Solution

$a=-\mu g$

$\because v=u+a t$

$0=20+(-\mu \times 10) \times 5$

$50 \mu=20$

$\mu=\frac{2}{5}=0.4$

Standard 11

Physics

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