A body of mass m is projected at an angle of {45^o} with horizontal. If air resistance is negligible

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4-1.Newton's Laws of Motion

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A body of mass $m$ is projected at an angle of ${45^o}$ with the horizontal. If air resistance is negligible, then total change in momentum when it strikes the ground is

A

$2mv$

B

$\sqrt 2 \,mv$

C

$mv$

D

$mv/\sqrt 2 $

Solution

(b) Change in momentum =$2mv\sin \theta $$ = 2mv\sin \frac{\pi }{4}$=$\sqrt 2 \;mv$

Standard 11

Physics

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