A ball of mass 0.15, mathrm{~kg} is dropped from a height 10, mathrm{~m} , strikes ground and reboun

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4-1.Newton's Laws of Motion

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A ball of mass $0.15\, \mathrm{~kg}$ is dropped from a height $10\, \mathrm{~m}$, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is $\left(\mathrm{g}=10 \,\mathrm{~m} / \mathrm{s}^{2}\right)$ nearly : (In $\mathrm{kg}\, \mathrm{m} / \mathrm{s}$)

A

$0$

B

$4.2$

C

$2.1$

D

$1.4$

(NEET-2021)

Solution

$v=\sqrt{2 g h}$

$v=\sqrt{2 \times 10 \times 10}$

$v=10 \sqrt{2}$

$I=2 \,m V$

$=2 \times 1.5 \times 10 \sqrt{2}$

$=3 \sqrt{2}$

$=3 \times 1.4=4.2\, \mathrm{kgm} / \mathrm{s}$

Standard 11

Physics

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