A body of mass 10 kg slides along a rough hor | vedclass

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Question

(c) Let $P$ force is acting at an angle $30^o $ with the horizontal.

For the condition of motion $F = \mu \;R$

$P\cos 30^\circ = \mu \,(mg

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(c) Let $P$ force is acting at an angle $30^o $ with the horizontal.

For the condition of motion $F = \mu \;R$

$P\cos 30^\circ = \mu \,(mg - P\sin 30^\circ )$

==> $P\frac{{\sqrt 3 }}{2} = \frac{1}{{\sqrt 3 }}\left( {100 - P\frac{1}{2}} ight)$

==>$\frac{{3P}}{2} = \left( {100 - \frac{P}{2}} ight)$

==> $2P = 100$ $	herefore \;\;P = 50\;N$

A body of mass $10$ kg slides along a rough horizontal surface. The coefficient of friction is $1/\sqrt 3 $. Taking $g = 10\,m/{s^2}$, the least force which acts at an angle of $30^o $ to the horizontal is ...... $N$

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