A body starts from rest. ratio of distance travelled by body during 4^{th} and 3^{rd} second

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2.Motion in Straight Line

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A body starts from rest. What is the ratio of the distance travelled by the body during the $4^{th}$ and $3^{rd}$ second

A$\frac{7}{5}$

B$\frac{5}{7}$

C$\frac{7}{3}$

D$\frac{3}{7}$

(AIPMT-1993)

Solution

(a) ${S_n} = u + \frac{a}{2}(2n – 1) = \frac{a}{2}(2n – 1)$ because $u = 0$
Hence $\frac{{{S_4}}}{{{S_3}}} = \frac{7}{5}$

Standard 11

Physics

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