A bullet fired into a fixed target loses half | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let initial velocity of the bullet $=u$

After penetrating $3 \mathrm{cm}$ its velocity becomes $\frac{\mathrm{u}}{2}$

From $v^{2}=u^{2}-2 a s$

$\le

Vedclass · Accepted Answer

$1$

Vedclass · Answer

Let initial velocity of the bullet $=u$

After penetrating $3 \mathrm{cm}$ its velocity becomes $\frac{\mathrm{u}}{2}$

From $v^{2}=u^{2}-2 a s$

$\left(\frac{\mathrm{u}}{2}\right)^{2}=\mathrm{u}^{2}-2 \mathrm{a}(3) \Rightarrow 6 \mathrm{a}=\frac{3 \mathrm{u}^{2}}{4} \Rightarrow \mathrm{a}=\frac{\mathrm{u}^{2}}{8}$

Let further it will penetrate through distance

$x$ and stops at point $C .$

For distance $B C, \mathrm{v}=0, \mathrm{u}=\mathrm{u} / 2, \mathrm{s}=\mathrm{x}, \mathrm{a}=\mathrm{u}^{2} / 8$

From

$v^{2}=u^{2}-2 a s \Rightarrow 0=\left(\frac{u}{2}\right)^{2}-2\left(\frac{u^{2}}{8}\right) \cdot x$

$\Rightarrow x=1 \mathrm{cm}$

A bullet fired into a fixed target loses half of its velocity after penetrating $3\, cm$. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?.......$cm$

Similar Questions

A particle is moving with constant acceleration $'a'.$ Following graph shows $v^{2}$ versus $x$ (displacement) plot. The acceleration of the particle is $......{m} / {s}^{2}$

If a train travelling at $72\,\, kmph$ is to be brought to rest in a distance of $200$ metres, then its retardation should be............$m{s^{ - 2}}$

If the velocity of a body related to displacement ${x}$ is given by $v=\sqrt{5000+24 {x}} \;{m} / {s}$, then the acceleration of the body is $\ldots \ldots {m} / {s}^{2}$

A lift performs the first part of its ascent with uniform acceleration $a$ and the remaining with uniform retardation $2a$. If $t$ is the time of ascent, find the depth of the shaft.