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2.Motion in Straight Line
hard
A body starts with an initial velocity of $10\,ms ^{-1}$ and is moving along a straight line with constant acceleration. When the velocity of the particle is $50\,ms ^{-1}$, the acceleration is reversed in direction. The velocity of the particle when it again reaches the starting point is $............\,m/s^{-1}$
A$70$
B$60$
C$10$
D$30$
Solution
(a)
$(50)^2=(10)^2+2 a s$
Now, $\quad v^2=(50)^2+2(-a)(-s)=(50)^2+2 a s$
Solving these two equations, we get
$v=70\,m / s$
$(50)^2=(10)^2+2 a s$
Now, $\quad v^2=(50)^2+2(-a)(-s)=(50)^2+2 a s$
Solving these two equations, we get
$v=70\,m / s$
Standard 11
Physics
