An automobile, travelling at 40, km/h, can be | vedclass

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Question

$\begin{array}{l}
According\,to\,question,\,{u_1} = 40\,km/h,\,{v_1} = 0\
and\,{s_1} = 40\,m\
{m{using}}\,{{m{v}}^2} - {u^2} = 2as;\,{0^2} -

Vedclass · Accepted Answer

$160$

Vedclass · Answer

$\begin{array}{l}
According\,to\,question,\,{u_1} = 40\,km/h,\,{v_1} = 0\
and\,{s_1} = 40\,m\
{m{using}}\,{{m{v}}^2} - {u^2} = 2as;\,{0^2} - {40^2} = 2a 	imes 40\,\,\,\,\,\,...\left( i ight)\
Again,\,{0^2} - {80^2} = 2as\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {ii} ight)\
From\,eqn.\left( i ight)\,and\,\left( {ii} ight)\,\
Stopping\,{m{ distance}},\,s = 160\,m\,\,
\end{array}$

An automobile, travelling at $40\, km/h$, can be stopped at a distance of $40\, m$ by applying brakes. If the same automobile is travelling at $80\, km/h$, the minimum stopping distance, in metres, is (assume no skidding)..........$m$

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