A body thrown vertically upwards with an initial velocity u reaches maximum height in 6 seconds. rat

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2.Motion in Straight Line

hard

A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in $6$ seconds. The ratio of the distances travelled by the body in the first second and the seventh second is

$1:1$

$11:1$

$1:2$

$1:11$

Solution

(b) Time of ascent $ = \frac{u}{g} = 6\;\sec \Rightarrow u = 60\;m/s$

Distance in first second ${h_{{\rm{first}}}} = 60 – \frac{g}{2}(2 \times 1 – 1) = 55\;m$

Distance in seventh second will be equal to the distance in first second of vertical downward motion ${h_{{\rm{seventh}}}} = \frac{g}{2}(2 \times 1 – 1) = 5\;m$

$⇒$ ${h_{{\rm{first}}}}/{h_{{\rm{seventh}}}}$$ = 11:1$

Standard 11

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Solution

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