A bomb is projected with $200\,m/s$ at an angle $60^o$ with horizontal. At the highest point, it explodes into three particles of equal masses. One goes vertically upward with velocity $100\,m/sec$, second particle goes vertically downward with the same velocity as the first. Then what is the velocity of the third one-
A bomb is projected with $200\,m/s$ at an angle $60^o$ with horizontal. At the highest point, it explodes into three particles of equal masses. One goes vertically upward with velocity $100\,m/sec$, second particle goes vertically downward with the same velocity as the first. Then what is the velocity of the third one-
- A
$120\, m/sec$ with $60^o$ angle
- B
$200 \,m/sec$ with $30^o$ angle
- C
$50\, m/sec$, in horizontal direction
- D
$300\, m/sec$, in horizontal direction
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