Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A force $\vec{F}=\hat{i}+4 \hat{j}$ acts on block shown. The force of friction acting on the block is

A

$-\hat{ i }$

B

$-1.8 \hat{i}$

C

$-2.4 \hat{i}$

D

$-3 \hat{i}$

Solution

$N =10-4=6\,N$

$f _{\max }=0.3 \times 6=1.8\,N$

But required $=1 N \leftarrow$ Force of friction $=-\hat{i}$

Standard 11
Physics

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