A bomb is projected with $200\,m/s$ at an angle $60^o$ with horizontal. At the highest point, it explodes into three particles of equal masses. One goes vertically upward with velocity $100\,m/sec,$ second particle goes vertically downward with the same velocity as the first. Then what is the velocity of the third one

  • A

    $120\,m/sec$ with $60^o$ angle

  • B

    $200\,m/sec$ with $30^o$ angle

  • C

    $50\,m/sec,$ in horizontal direction

  • D

    $300\,m/sec,$ in horizontal direction

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