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4-1.Newton's Laws of Motion
easy
A player caught a cricket ball of mass $150\, gm$ moving at the rate of $20 \,m/sec$. if the catching process be completed in $ 0.1 \,sec$ the force of the blow exerted by the ball on the hands of player is ........... $N$
A$0.3$
B$30 $
C$300$
D$3000$
Solution
(b) Force exerted by the ball
$⇒$ $F = m\;\left( {\frac{{dv}}{{dt}}} \right) = 0.15 \times \frac{{20}}{{0.1}} = 30\;N$
$⇒$ $F = m\;\left( {\frac{{dv}}{{dt}}} \right) = 0.15 \times \frac{{20}}{{0.1}} = 30\;N$
Standard 11
Physics
