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5.Work, Energy, Power and Collision
medium
A bomb of $12\, kg$ explodes into two pieces of masses $4\, kg$ and $8\, kg$. The velocity of $8\, kg$ mass is $6\, m/sec$. The kinetic energy of the other mass is .............. $\mathrm{J}$
A$48$
B$32$
C$24$
D$288$
Solution
After explosion the momentum of both the
blocks is zero. Hence
$4 v=8 \times 6$ or $v=12 \mathrm{m} / \mathrm{s}$
$KE.$ of $4 \mathrm{kg}$ body $=\frac{1}{2} \times 4 \times 144=288 \mathrm{J}$
blocks is zero. Hence
$4 v=8 \times 6$ or $v=12 \mathrm{m} / \mathrm{s}$
$KE.$ of $4 \mathrm{kg}$ body $=\frac{1}{2} \times 4 \times 144=288 \mathrm{J}$
Standard 11
Physics