A particle of mass ${m_1}$ is moving with a velocity ${v_1}$and another particle of mass ${m_2}$is moving with a velocity ${v_2}$. Both of them have the same momentum but their different kinetic energies are ${E_1}$and ${E_2}$respectively. If ${m_1} > {m_2}$ then
${E_1} < {E_2}$
$\frac{{{E_1}}}{{{E_2}}} = \frac{{{m_1}}}{{{m_2}}}$
${E_1} > {E_2}$
${E_1} = {E_2}$
Two bodies $A$ and $B$ having masses in the ratio of $3 : 1$ possess the same kinetic energy. The ratio of their linear momenta is then
The momentum of a body is increased by $50 \%$. The percentage increase in the kinetic energy of the body is $...........\,\%$
The kinetic energy of a body of mass $2 kg $ and momentum of $2 Ns$ is ............. $\mathrm{J}$
The graph between $E$ and $v$ is