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5.Work, Energy, Power and Collision
medium
A bomb of mass $9 \,kg$ explodes into two pieces of masses $3 \,kg$ and $6 \,kg$. The velocity of mass $3 \,kg$ is $16 \,m / s$. The kinetic energy of mass $6 \,kg$ in joule is
A$196$
B$320$
C$192$
D$620$
Solution
(c)
Using momentum conservation
$0=m_1 V_1+m_2 v_2$
$V_2=-\frac{3 \times 16}{6}$
$=-8 \,m / s$
$\text { K.E. }=\frac{1}{2} m v^2=\frac{1}{2}(6)(8)^2=192 \,J$
Using momentum conservation
$0=m_1 V_1+m_2 v_2$
$V_2=-\frac{3 \times 16}{6}$
$=-8 \,m / s$
$\text { K.E. }=\frac{1}{2} m v^2=\frac{1}{2}(6)(8)^2=192 \,J$
Standard 11
Physics
