A box containing $4$ white pens and $2$ black pens. Another box containing $3$ white pens and $5$ black pens. If one pen is selected from each box, then the probability that both the pens are white is equal to

For independent events ${A_1},\,{A_2},\,..........,{A_n},$ $P({A_i}) = \frac{1}{{i + 1}},$ $i = 1,\,\,2,\,......,\,\,n.$ Then the probability that none of the event will occur, is

Cards are drawn one by one without replacement from a pack of $52$ cards. The probability that $10$ cards will precede the first ace is

The probability of happening an event $A$ is $0.5$ and that of $B$ is $0.3$. If $A$ and $B$ are mutually exclusive events, then the probability of happening neither $A$ nor $B$ is

Two players play the following game: $A$ writes $3,5,6$ on three different cards: $B$ writes $8,9,10$ on three different cards. Both draw randomly two cards from their collections. Then, $A$ computes the product of two numbers helshe has drawn, and $B$ computes the sum of two numbers he/she has drawn. The player getting the larger number wins. What is the probability that A wins?

Three persons work independently on a problem. If the respective probabilities that they will solve it are $\frac{{1}}{{3}} , \frac{{1}}{{4}}$ and $\frac{{1}}{{5}}$, then the probability that none can solve it