A box contains 6 nails and 10 nuts. Half of nails and half of nuts are rusted. If one item is chosen

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14.Probability

easy

A box contains $6$ nails and $10$ nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, what is the probability that it is rusted or is a nail

A

$\frac{3}{{16}}$

B

$\frac{5}{{16}}$

C

$\frac{{11}}{{16}}$

D

$\frac{{14}}{{16}}$

Solution

(c) Total rusted items $ = 3 + 5 = 8\,;$ unrusted nails $ = 3$.

$\therefore $ Required probability $ = \frac{{3 + 8}}{{6 + 10}} = \frac{{11}}{{16}}.$

Standard 11

Mathematics

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(JEE MAIN-2023)