A box contains 25 tickets numbered 1, 2, ....... 25 . If two tickets are drawn at random then probab

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14.Probability

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A box contains $25$ tickets numbered $1, 2, ....... 25$. If two tickets are drawn at random then the probability that the product of their numbers is even, is

A

$\frac{{11}}{{50}}$

B

$\frac{{13}}{{50}}$

C

$\frac{{37}}{{50}}$

D

None of these

Solution

(c) Required probability is $1 – P$ (Both odd numbers are chosen)

$ = 1 – \frac{{{}^{13}{C_2}}}{{{}^{25}{C_2}}} = 1 – \frac{{13\,.\,12}}{{25\,.\,24}} = \frac{{37}}{{50}}.$

Standard 11

Mathematics

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