A box contains 25 tickets numbered 1, 2, .... | vedclass

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Question

(c) Required probability is $1 - P$  (Both odd numbers are chosen)

$ = 1 - \frac{{{}^{13}{C_2}}}{{{}^{25}{C_2}}} = 1 - \frac{{13\,.\,12}}{{25\

Vedclass · Accepted Answer

$\frac{{37}}{{50}}$

Vedclass · Answer

(c) Required probability is $1 - P$  (Both odd numbers are chosen)

$ = 1 - \frac{{{}^{13}{C_2}}}{{{}^{25}{C_2}}} = 1 - \frac{{13\,.\,12}}{{25\,.\,24}} = \frac{{37}}{{50}}.$

A box contains $25$ tickets numbered $1, 2, ....... 25$. If two tickets are drawn at random then the probability that the product of their numbers is even, is

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