A box contains 10 red balls and 15 green balls. If two balls are drawn in succession then probabilit

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14.Probability

easy

A box contains $10$ red balls and $15$ green balls. If two balls are drawn in succession then the probability that one is red and other is green, is

A

$\frac{1}{3}$

B

$\frac{1}{2}$

C

$\frac{1}{4}$

D

None of these

Solution

(b) Required probability $ = \frac{{(10\,.\,15)}}{{{}^{25}{C_2}}} = \left( {\frac{{2\,.\,10\,.\,15}}{{25\,.\,24}}} \right) = \frac{1}{2}.$

Standard 11

Mathematics

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