The probability of getting $4$ heads in $8$ throws of a coin, is
$\frac{1}{2}$
$\frac{1}{{64}}$
$\frac{{^8{C_4}}}{8}$
$\frac{{^8{C_4}}}{{{2^8}}}$
(d) Required probability $ = \frac{{{}^8{C_4}}}{{{2^8}}}.$
A multiple choice examination has $5$ questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get $4$ or more correct answers just by guessing is :
A purse contains $4$ copper coins $\& \, 3$ silver coins, the second purse contains $6$ copper coins $\& \,2$ silver coins. If a coin is drawn out of one of these purses, then the probability that it is a copper coin is :-
If $12$ identical balls are to be placed randomly in $3$ identical boxes, then the probability that one of the boxes contains exactly $3$ balls is
A box contains $15$ tickets numbered $1, 2, ……. 15$. Seven tickets are drawn at random one after the other with replacement. The probability that the greatest number on a drawn ticket is $9$, is
In a lottery there were $90$ tickets numbered $1$ to $90$. Five tickets were drawn at random. The probability that two of the tickets drawn numbers $15$ and $89$ is
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