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14.Probability
easy
A box contains $24$ identical balls, of which $12$ are white and $12$ are black. The balls are drawn at random from the box one at a time with replacement. The probability that a white ball is drawn for the $4^{th}$ time on the $7^{th}$ draw is
A
$\frac{5}{{64}}$
B
$\frac{{27}}{{32}}$
C
$\frac{5}{{32}}$
D
$\frac{1}{2}$
(IIT-1994)
Solution
(c) To get $3$ white balls in first $6$ draw and then a white again in $7^{th}$ draws.
$P = {}^6{C_3} \times {\left( {\frac{1}{2}} \right)^3}\left( {\frac{1}{2}} \right){\rm{ }}\left( {\frac{1}{2}} \right) \Rightarrow P = \frac{5}{{32}}$.
Standard 11
Mathematics