14.Probability
easy

A box contains $24$ identical balls, of which $12$ are white and $12$ are black. The balls are drawn at random from the box one at a time with replacement. The probability that a white ball is drawn for the $4^{th}$ time on the $7^{th}$ draw is

A

$\frac{5}{{64}}$

B

$\frac{{27}}{{32}}$

C

$\frac{5}{{32}}$

D

$\frac{1}{2}$

(IIT-1994)

Solution

(c) To get $3$ white balls in first $6$ draw and then a white again in $7^{th}$ draws.

$P = {}^6{C_3} \times {\left( {\frac{1}{2}} \right)^3}\left( {\frac{1}{2}} \right){\rm{ }}\left( {\frac{1}{2}} \right) \Rightarrow P = \frac{5}{{32}}$.

Standard 11
Mathematics

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