A bulb and a capacitor are connected in series to a source of alternating current. If its frequency

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7.Alternating Current

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A bulb and a capacitor are connected in series to a source of alternating current. If its frequency is increased, while keeping the voltage of the source constant, then

Bulb will give more intense light

Bulb will give less intense light

Bulb will give light of same intensity as before

Bulb will stop radiating light

Solution

(a) When a bulb and a capacitor are connected in series to an $ac$ source, then on increasing the frequency the current in the circuit is increased, because the impedance of the circuit is decreased. So the bulb will give more intense light.

Standard 12

Physics

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There is no resistance in the inductive circuit. Kirchhoff 's voltage law for the circuit is

easy

Two resistors of $10\, \Omega$ and $20\, \Omega$ and an ideal inductor of $10\, H$ are connected to a $2\, V$ battery as shown. The key $K$ is inserted at time $t = 0$. The initial $(t = 0)$ and final ($t \rightarrow \infty$ ) currents through battery are

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Explain $AC$ voltage applied to a resistor and explain it with necessary graph.

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The equation of current in a purely inductive circuit is $5 \sin \left(49 \pi t-30^{\circ}\right)$. If the inductance is $30\,mH$ then the equation for the voltage across the inductor, will be.$\left\{\right.$ Let $\left.\pi=\frac{22}{7}\right\}$

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(JEE MAIN-2022)

A bulb and a capacitor are connected in series to a source of alternating current. If its frequency is increased, while keeping the voltage of the source constant, then

Solution

Similar Questions

At a moment $(t = 0)$ when charge on capacitor $C_1$ is zero, the switch is closed. If $I_0$ be the current through inductor at that instant, for $t > 0,$

There is no resistance in the inductive circuit. Kirchhoff 's voltage law for the circuit is

Two resistors of $10\, \Omega$ and $20\, \Omega$ and an ideal inductor of $10\, H$ are connected to a $2\, V$ battery as shown. The key $K$ is inserted at time $t = 0$. The initial $(t = 0)$ and final ($t \rightarrow \infty$ ) currents through battery are

Explain $AC$ voltage applied to a resistor and explain it with necessary graph.

The equation of current in a purely inductive circuit is $5 \sin \left(49 \pi t-30^{\circ}\right)$. If the inductance is $30\,mH$ then the equation for the voltage across the inductor, will be.$\left\{\right.$ Let $\left.\pi=\frac{22}{7}\right\}$

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