Equation of current in a purely inductive circuit is 5 sin left(49 π t-30^{circ}right) . If inducta

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7.Alternating Current

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The equation of current in a purely inductive circuit is $5 \sin \left(49 \pi t-30^{\circ}\right)$. If the inductance is $30\,mH$ then the equation for the voltage across the inductor, will be.$\left\{\right.$ Let $\left.\pi=\frac{22}{7}\right\}$

A

$1.47 \sin \left(49 \pi t -30^{\circ}\right)$

B

$1.47 \sin \left(49 \pi t+60^{\circ}\right)$

C

$23.1 \sin \left(49 \pi t -30^{\circ}\right)$

D

$23.1 \sin \left(49 \pi t+60^{\circ}\right)$

(JEE MAIN-2022)

Solution

$v _{0}= i _{0} x _{ L }$

$= i _{0}( wL )$

$=(5)(49 \pi)\left(30 \times 10^{-3}\right)$

$=23.1$

Voltage will lead current by $90^{\circ}$.

$\therefore V =23.1 \sin \left(49 \pi t +60^{\circ}\right)$

Standard 12

Physics

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