A bullet fired into a fixed target loses half | vedclass

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Question

$A$ to $B$$:$ $\left(\frac{\mathrm{u}}{2}ight)^{2}=\mathrm{u}^{2}-2 \mathrm{a} 	imes 1$      $...(i)$
$\mathrm{B}$ to $\mathrm{C}:

Vedclass · Accepted Answer

$\frac {1}{3}\,cm$

Vedclass · Answer

$A$ to $B$$:$ $\left(\frac{\mathrm{u}}{2}ight)^{2}=\mathrm{u}^{2}-2 \mathrm{a} 	imes 1$      $...(i)$
$\mathrm{B}$ to $\mathrm{C}: 0=\left(\frac{\mathrm{u}}{2}ight)^{2}-2 \mathrm{a} 	imes \mathrm{d}$        $...(ii)$
From $(	ext { i }), 2 a=\frac{3 u^{2}}{4}$ in $(	ext { ii })$
$0=\frac{\mathrm{u}^{2}}{4}-\frac{3 \mathrm{u}^{2}}{4} \mathrm{d} \quad \Rightarrow \mathrm{d}=\frac{1}{3} \mathrm{cm}$

A bullet fired into a fixed target loses half of its velocity after penetrating $1\,cm.$ How much further it will penetrate before coming to rest, assuming that it faces constant resistance to motion

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