A three-wheeler starts from rest, accelerates uniformly with $1\; m/s^{2}$ on a straight road for $10\; s$, and then moves with uniform velocity. Plot the distance covered by the vehicle during the $n ^{\text {th }}$ second $( n =1,2,3 \ldots .)$ versus $n$. What do you expect this plot to be during accelerated motion : a straight line or a parabola?

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Straight line

Distance covered by a body in $n^{\text {th }}$ second is given by the relation $D_{n}=u+\frac{a}{2}(2 n-1)\ldots(i)$

Where,

$u=$ Initial velocity

$a=$ Acceleration

$n=$ Time $=1,2,3, \ldots \ldots, n$

In the given case, $u=0$ and $a=1 m / s ^{2}$

$\therefore D_{n}=\frac{1}{2}(2 n-1)\dots (ii)$

This relation shows that

$D_{n} \propto n \ldots (iii)$

Now, substituting different values of $n$ in equation (iii), we get the following table

$n$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$ $9$ $10$
$D_n$ $0.5$ $1.5$ $2.5$ $3.5$ $4.5$ $5.5$ $6.5$ $7.5$ $8.5$ $9.5$

The plot between $n$ and $D_{n}$ will be a straight line as shown

since the given three-wheeler acquires uniform velocity after 10 s, the line will be parallel to the time-axis after $n=10 s$

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