A bullet is fired from a cannon with velocity 500 ,m/s . If angle of projection is {15^o} and g = 10

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3-2.Motion in Plane

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A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is

A

$25 \times {10^3}m$

B

$12.5 \times {10^3}m$

C

$50 \times {10^2}m$

D

$25 \times {10^2}m$

Solution

(b) $R = \frac{{{u^2}\sin 2\theta }}{g} = \frac{{{{(500)}^2} \times \sin 30^\circ }}{{10}} = 12.5 \times {10^3}\,m$

Standard 11

Physics

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