A stone is projected at angle 30^{circ} to horizontal. ratio of kinetic energy of stone at point of

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3-2.Motion in Plane

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A stone is projected at angle $30^{\circ}$ to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be :

A

$1: 2$

B

$1: 4$

C

$4: 1$

D

$4: 3$

(JEE MAIN-2023)

Solution

$\frac{ KE _{ POP }}{ KE _{\text {top }}}=\frac{\frac{1}{2} M ( u )^2}{\frac{1}{2} M \left( u \cos 30^{\circ}\right)^2}=\frac{4}{3}$

Standard 11

Physics

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