A bullet of mass 0.1,kg is fired with a speed of 100, m/sec , mass of gun is 50, kg . velocity of re

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4-1.Newton's Laws of Motion

easy

A bullet of mass $0.1\,kg$ is fired with a speed of $100\, m/sec$, the mass of gun is $50\, kg$. The velocity of recoil is ........ $m/sec$

A

$0.2$

B

$0.1$

C

$0.5 $

D

$0.05 $

Solution

(a) According to principle of conservation of linear momentum, ${m_G}{v_G} = {m_B}{v_B}$

$ \Rightarrow {v_G} = \frac{{{m_B}{v_B}}}{{{m_G}}} = \frac{{0.1 \times {{10}^2}}}{{50}} = 0.2m/s$

Standard 11

Physics

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