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4-1.Newton's Laws of Motion
easy
$50\, kg$ દળની મશીનગનમાંથી $0.1\,kg$ ની ગોળી $100\,m/s$ ના વેગથી છોડતાં મશીનગનનો વેગ ........ $m/sec$ થાય.
A
$0.2$
B
$0.1$
C
$0.5$
D
$0.05$
Solution
(a) According to principle of conservation of linear momentum, ${m_G}{v_G} = {m_B}{v_B}$
$ \Rightarrow {v_G} = \frac{{{m_B}{v_B}}}{{{m_G}}} = \frac{{0.1 \times {{10}^2}}}{{50}} = 0.2m/s$
Standard 11
Physics
