A bullet of mass 10 ,g moving with a speed of 20 ,m / s hits an ice block of mass 990 ,g kept on a f

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A bullet of mass $10 \,g$ moving with a speed of $20 \,m / s$ hits an ice block of mass $990 \,g$ kept on a frictionless floor and gets stuck in it. How much ice will melt if $50 \%$ of the lost KE goes to ice is .......... $g$ (initial temperature of the ice block and bullet $=0^{\circ} C$ )

A

$0.001$

B

$0.002$

C

$0.003$

D

$0.004$

Solution

(c)

$50 \%$ of lost KE goes to melt ice

$\Rightarrow \frac{1}{2} \times \frac{1}{2} \times \frac{10 \times 20 \times 20}{1000}=1\, J$

Amount of ice that melts $=\frac{1}{80 \times 4.2}=0.003 \,g$

Standard 11

Physics

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