Gujarati
Hindi
10-1.Thermometry, Thermal Expansion and Calorimetry
hard

When $x\, grams$ of steam at $100\,^oC$ is mixed  with $y\,grams$ of ice at $0\,^oC$ , We obtain $(x + y)\,grams$ of water at $100\,^oC$  . What is the ratio $y/x$ ?

A

$1$

B

$2$

C

$3$

D

$4$

Solution

Heat given out when $x$ grams of steam at $100^{\circ} \mathrm{C}$ is converted to water at $100^{\circ} \mathrm{C}$

$\mathrm{H}_{1}=540 x \ldots(1)$

Heat gained by ice at $0^{\circ} \mathrm{C}$ to converted to water at $100^{\circ} \mathrm{C}$ $\mathrm{H}_{2}=80 \mathrm{y}+\mathrm{y} \times 1 \times(100-0)$

$\mathrm{H}_{2}=180 \mathrm{y} \cdots(2)$

Acording to principle of calorimetry

$\mathrm{H}_{1}=\mathrm{H}_{2}$

$540 \mathrm{x}=180 \mathrm{y}$

$\frac{y}{x}=3$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.