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10-1.Thermometry, Thermal Expansion and Calorimetry
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When $x\, grams$ of steam at $100\,^oC$ is mixed with $y\,grams$ of ice at $0\,^oC$ , We obtain $(x + y)\,grams$ of water at $100\,^oC$ . What is the ratio $y/x$ ?
A
$1$
B
$2$
C
$3$
D
$4$
Solution
Heat given out when $x$ grams of steam at $100^{\circ} \mathrm{C}$ is converted to water at $100^{\circ} \mathrm{C}$
$\mathrm{H}_{1}=540 x \ldots(1)$
Heat gained by ice at $0^{\circ} \mathrm{C}$ to converted to water at $100^{\circ} \mathrm{C}$ $\mathrm{H}_{2}=80 \mathrm{y}+\mathrm{y} \times 1 \times(100-0)$
$\mathrm{H}_{2}=180 \mathrm{y} \cdots(2)$
Acording to principle of calorimetry
$\mathrm{H}_{1}=\mathrm{H}_{2}$
$540 \mathrm{x}=180 \mathrm{y}$
$\frac{y}{x}=3$
Standard 11
Physics
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