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A bus decreases its speed from $80\, km\, h ^{-1}$ to $60 \,km\, h ^{-1}$ in $5\, s$. Find the acceleration(in $m / s ^{2}$) of the bus.
A
$4.44$
B
$-1.112$
C
$-2.112$
D
$7.77$
Solution
Initial speed of the bus, $=80 \times \frac{5}{18}=22.22 \,m / s$
Final speed of the bus, $=60 \times \frac{5}{18}=16.66\, m / s$
Time take to decrease the speed, $t=5 \,s$
Acceleration, $a =\frac{v-u}{t}=\frac{16.66-22.22}{5}=-1.112\, m / s ^{2}$
Standard 9
Science
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