A bus decreases its speed from $80\, km\, h^{-1}$ to $50 \,km h ^{-1}$ in $4\, s$. Find the acceleration of the bus.
Given $v=50 km h ^{-1}=50 \times \frac{5}{18}=\frac{125}{9} m s ^{-1}$
$u=80 km h ^{-1}=80 \times \frac{5}{18}=\frac{200}{9} m s ^{-1}$
$t=4 s$
Using the expression $v=u+a t,$ we have
$a=\frac{v-u}{t}=\frac{125-200}{9 \times 4}=-2.083 m s ^{-2}$
Define distance and displacement. A body covers one complete revolution around a circular park of circumference $176 \,m$ in $4$ minutes. Find the displacement of the body after $6$ minutes.
A body thrown in the vertically upward direction rises upto a height $'h^{\prime}$ and comes back to the position of its start.
Calculate :
$(a)$ the total distance travelled by the body and
$(b)$ the displacement of the body. Under what condition will the magnitude of the displacement be equal to the distance travelled by an object ?
$(a)$ Write differences between speed and velocity.
$(b)$ The speed of a moving object is $x m s ^{-1}$. Its velocity is $y m s ^{-1}$. What is the similarity observed ?
If the acceleration of a particle is constant in magnitude but not in direction, what type of path is followed by the particle ?
Identify what do the graphs shown below indicate ?