A butterfly is flying with a velocity 4 sqrt{ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\overrightarrow{{V}}_{{BW}}=4 \sqrt{2} \cos 45 \hat{{i}}+4 \sqrt{2} \sin 45 \hat{{j}}$

$=4 \hat{{i}}+4 \hat{{j}}$

$\overrightarrow{{V}}_{{w}}=-

Vedclass · Accepted Answer

$15$

Vedclass · Answer

$\overrightarrow{{V}}_{{BW}}=4 \sqrt{2} \cos 45 \hat{{i}}+4 \sqrt{2} \sin 45 \hat{{j}}$

$=4 \hat{{i}}+4 \hat{{j}}$

$\overrightarrow{{V}}_{{w}}=-\hat{{j}}$

$\overrightarrow{{V}}_{{B}}=\overrightarrow{{V}}_{{Bw}}+\overrightarrow{{V}}_{{T}}=4 \hat{{i}}+3 \hat{{j}}$

$\overrightarrow{{S}}_{{B}}=\overrightarrow{{V}}_{{B}} 	imes {t}=(4 \hat{{i}}+3 \hat{{j}}) 	imes 3=12 \hat{{i}}+9 \hat{{j}}$

$\left|\overrightarrow{{S}}_{{B}}ight|=\sqrt{(12)^{2}+(9)^{2}}=15\, {m}$

A butterfly is flying with a velocity $4 \sqrt{2} \,{m} / {s}$ in North-East direction. Wind is slowly blowing at $1$ ${m} / {s}$ from North to South. The resultant displacement of the butterfly in $3\, seconds$ is $....\,{m}.$

Similar Questions

A boat crosses a river with a velocity of $8\, km/h$. If the resulting velocity of boat is $10 \,km/h $ then the velocity of river water is...........$km/h$

Figure shows two ships moving in $x-y$ plane with velocities $V_A$ and $V_B$. The ships move such that $B$ always remains north of $A$. The ratio $\frac{V_A}{V_B}$ is equal to ........

A swimmer can swim with speed '$v$' with respect to still water in a river which is flowing with speed $u$. There is a float moving with the river. Now the swimmer overtakes float and gets a lead of $l$ and returns back to the float. Time taken by swimmer in this process will be

A boat covers certain distance between two spots in a river taking $t_1$ hrs going downstream and $t_2$ hrs going upstream. What time will be taken by boat to cover same distance in still water?