A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in
Reduction of charge on the plates and increase of potential difference across the plates
Increase in the potential difference across the plates, reduction in stored energy, but no change in the charge on the plates.
Decrease in the potential difference across the plates, reduction in stored energy, but no change in the charge on the plates
None of the above
A particle of charge $Q$ and mass $m$ travels through a potential difference $V$ from rest. The final momentum of the particle is
Electric field at a point varies as $r^o$ for
Electric potential at any point is : $V = -5x + 3y + \sqrt {15} z$ ; then the magnitude of electric field is :-
Three point charges $+q, -2q$ and $+q$ are placed at points $(x = 0, y = a, z = 0), (x = 0, y = 0,z = 0)$ and $(x = a, y = 0, z = 0)$ respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
A parallel plate capacitor of capacitance $C$ is connected to a battery and is charged to a potential difference $V$. Another capacitor of capacitance $2C$ is connected to another battery and is charged to potential difference $2V$ . The charging batteries are now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is