As shown in the fig. charges $+\,q$ and $-\,q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is
$\frac{1}{{4\pi { \in _0}}}.\frac{{2q}}{{\sqrt {{a^2} + {b^2}} }}$
zero
$\frac{1}{{4\pi { \in _0}}}.\frac{{q}}{{\sqrt {{a^2} + {b^2}} }}$
$\frac{1}{{4\pi { \in _0}}}.\frac{{-q}}{{\sqrt {{a^2} + {b^2}} }}$
Two equal point charges are fixed at $x = -a$ and $x = + \,a$ on the $x$-axis. Another point charge $Q$ is placed at the origin. The change in the electrical potential energy of $Q$ ehen it is displaced by a small distance $x$ along the $x$ -axis is apporximately proportional to
Electric potential at an equatorial point of a small dipole with dipole moment $P$ ( $r$ , distance from the dipole) is
Charge of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor if capacitance of capacitor is $C$ find potential difference between the plates
Which of the following is a volt :
If there are $n$ capacitors in parallel connected to $V \,volt$ source, then the energy stored is equal to