A capacitor is charged with a battery and energy stored is $U$. After disconnecting battery another capacitor of same capacity is connected in parallel to the first capacitor. Then energy stored in each capacitor is
$4U$
$\frac{U}{4}$
$2U$
$\frac{U}{2}$
If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to
A $6\,\mu F$ capacitor is charged from $10\;volts$ to $20\;volts$. Increase in energy will be
A parallel plate capacitor of capacity ${C_0}$ is charged to a potential ${V_0}$
$(i)$ The energy stored in the capacitor when the battery is disconnected and the separation is doubled ${E_1}$
$(ii)$ The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is ${E_2}.$
Then ${E_1}/{E_2}$ value is
A $10\, micro-farad$ capacitor is charged to $500\, V$ and then its plates are joined together through a resistance of $10\, ohm$. The heat produced in the resistance is........$J$
The energy of a charged capacitor resides in