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2. Electric Potential and Capacitance
easy
A capacitor of capacitance $C$ is charged with the help of a $200 \,V$ battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $2.5 \times 10^2 \,J / kg$ and mass $0.1 \,kg$. If the temperature of the block rises by $0.4 \,K$, the value of $C$ is
A
$500 \,F$
B
$500 \,\mu F$
C
$50 \,F$
D
$50 \,\mu F$
Solution
(b)
$\frac{1}{2} \times C \times(200)^2=2.5 \times 10^2 \times 0.1 \times 0.4$
$2 \times 10^4 C=1 \times 10$
$C=\frac{1}{2 \times 10^3}=500 \,\mu F$
Standard 12
Physics
