As in figure shown, if a capacitor $C$ is charged by connecting it with resistance $R$, then energy is given by the battery will be
$\frac{1}{2}C{V^2}$
More than$\frac{1}{2}C{V^2}$
Less than $\frac{1}{2}C{V^2}$
Zero
A series combination of $n_1$ capacitors, each of value $C_1$ is charged by a source of potential difference $4\, V.$ When another parallel combination of $n_2$ capacitors, each of value $C_2,$ is charged by a source of potential difference $V$, it has the same (total) energy stored in it, as the first combination has. The value of $C_2,$ in terms of $C_1$ is then
A $6\,\mu F$ capacitor is charged from $10\;volts$ to $20\;volts$. Increase in energy will be
Two capacitors of capacitances $C$ and $2\, C$ are charged to potential differences $V$ and $2\, V$, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is$.....CV^2$
In a charged capacitor, the energy resides
Intially, switch $S$ is connected to position $1$ for a long time shown in figure. The net amount of heat generated in the circuit after it is shifted to position $2$ is