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4-1.Newton's Laws of Motion
hard
A car is moving on a circular path and takes a turn. If ${R_1}$ and ${R_2}$ be the reactions on the inner and outer wheels respectively, then
A${R_1} = {R_2}$
B${R_1} < {R_2}$
C${R_1} > {R_2}$
D${R_1} \ge {R_2}$
Solution
(b) Reaction on inner wheel ${R_1} = \frac{1}{2}M\left[ {g – \frac{{{v^2}h}}{{ra}}} \right]$
Reaction on outer wheel ${R_2} = \frac{1}{2}M\left[ {g + \frac{{{v^2}h}}{{ra}}} \right]$
where, $r =$ radius of circular path, $2a =$ distance between two wheels and $h = $ height of centre of gravity of car.
Reaction on outer wheel ${R_2} = \frac{1}{2}M\left[ {g + \frac{{{v^2}h}}{{ra}}} \right]$
where, $r =$ radius of circular path, $2a =$ distance between two wheels and $h = $ height of centre of gravity of car.
Standard 11
Physics
