- Home
- Standard 11
- Physics
4-1.Newton's Laws of Motion
easy
A person with his hands in his pockets is skating on ice at the velocity of $10 \,m/s$ and describes a circle of radius $50\, m$. What is his inclination with vertical
A${\tan ^{ - 1}}\left( {\frac{1}{10}} \right)$
B${\tan ^{ - 1}}\left( {\frac{3}{5}} \right)$
C${\tan ^{ - 1}}(1)$
D${\tan ^{ - 1}}\left( {\frac{1}{5}} \right)$
Solution
(d) The inclination of person from vertical is given by,
$\tan \theta = \frac{{{v^2}}}{{rg}} = \frac{{{{(10)}^2}}}{{50 \times 10}} = \frac{1}{5}$
$⇒$ $\theta = {\tan ^{ – 1}}(1/5)$
$\tan \theta = \frac{{{v^2}}}{{rg}} = \frac{{{{(10)}^2}}}{{50 \times 10}} = \frac{1}{5}$
$⇒$ $\theta = {\tan ^{ – 1}}(1/5)$
Standard 11
Physics
