A car is moving on an overbridge of radius R | vedclass

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Question

From figure reaction of normal force on the motor cyclist

$m g \cos 	heta-R=\frac{m v^{2}}{r_{m}^{2}}$

$R=m g \cos 	heta-\frac{m v^{2}}{r}$

Vedclass · Accepted Answer

decreases

Vedclass · Answer

From figure reaction of normal force on the motor cyclist

$m g \cos 	heta-R=\frac{m v^{2}}{r_{m}^{2}}$

$R=m g \cos 	heta-\frac{m v^{2}}{r}$

As motorcycle ascend on the over bridge, angle of inclination of motorcycle with vertical decreases and becomes zero at at the highest point so'cos $	heta^{\prime}$ goes on increasing and becomes $1\, at$ highest point value of $R$ is continuously increasing while ascending.

A car is moving on an overbridge of radius $R$ with a constant speed $v$. As the car is descending on the overbridge from point $B$ to $C,$ the normal reaction on it due to bridge

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