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3-2.Motion in Plane
medium
A car is moving on an overbridge of radius $R$ with a constant speed $v$. As the car is descending on the overbridge from point $B$ to $C,$ the normal reaction on it due to bridge
Aincreases
Bdecreases
Cremains constant
Dfirst increases and then decreases
Solution
From figure reaction of normal force on the motor cyclist
$m g \cos \theta-R=\frac{m v^{2}}{r_{m}^{2}}$
$R=m g \cos \theta-\frac{m v^{2}}{r}$
As motorcycle ascend on the over bridge, angle of inclination of motorcycle with vertical decreases and becomes zero at at the highest point so'cos $\theta^{\prime}$ goes on increasing and becomes $1\, at$ highest point value of $R$ is continuously increasing while ascending.
$m g \cos \theta-R=\frac{m v^{2}}{r_{m}^{2}}$
$R=m g \cos \theta-\frac{m v^{2}}{r}$
As motorcycle ascend on the over bridge, angle of inclination of motorcycle with vertical decreases and becomes zero at at the highest point so'cos $\theta^{\prime}$ goes on increasing and becomes $1\, at$ highest point value of $R$ is continuously increasing while ascending.
Standard 11
Physics
