- Home
- Standard 11
- Physics
3-2.Motion in Plane
medium
If the string of a conical pendulum makes an angle $\theta$ with horizontal, then square of its time period is proportional to
A$\sin \theta$
B$\cos \theta$
C$\tan \theta$
D$\cot \theta$
Solution
(a)For conical pendulum we know that
$T=2 \pi \sqrt{\frac{l \cos \theta}{g}}$
where $\theta$ is the angle from vertical but in question $\theta$ is given from horizontal hence
$T=2 \pi \sqrt{\frac{l \sin \theta}{g}}$
$T^2 \propto \sin \theta$
Standard 11
Physics
