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2.Motion in Straight Line
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A car moves a distance of $200 \;m$. It covers the first half of the distance at speed $40 \;km / h$ and the second half of distance at speed $v$. The average speed is $48\; km / h$. The value of $v$ is
A
$56$
B
$60$
C
$50$
D
$48$
(AIPMT-1991)
Solution
Total distance travelled $=200 m$
Total time taken $=\frac{100}{40}+\frac{100}{v}$
Average speed $=\frac{\text { total distance travelled }}{\text { total time taken }}$
$48=\frac{200}{\left(\frac{100}{40}+\frac{100}{v}\right)}$
$48=\frac{2}{\left(\frac{1}{40}+\frac{1}{v}\right)}$
$\frac{1}{40}+\frac{1}{v}=\frac{1}{24}$
$\frac{1}{v}=\frac{1}{24}-\frac{1}{40}=\frac{5-3}{120}=\frac{1}{60}$
$v=60 km / hr$
Standard 11
Physics
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