2.Motion in Straight Line
medium

A car moves a distance of $200 \;m$. It covers the first half of the distance at speed $40 \;km / h$ and the second half of distance at speed $v$. The average speed is $48\; km / h$. The value of $v$ is

A

$56$

B

$60$

C

$50$

D

$48$

(AIPMT-1991)

Solution

Total distance travelled $=200 m$

Total time taken $=\frac{100}{40}+\frac{100}{v}$

Average speed $=\frac{\text { total distance travelled }}{\text { total time taken }}$

$48=\frac{200}{\left(\frac{100}{40}+\frac{100}{v}\right)}$

$48=\frac{2}{\left(\frac{1}{40}+\frac{1}{v}\right)}$

$\frac{1}{40}+\frac{1}{v}=\frac{1}{24}$

$\frac{1}{v}=\frac{1}{24}-\frac{1}{40}=\frac{5-3}{120}=\frac{1}{60}$

$v=60 km / hr$

Standard 11
Physics

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