A car moving with a speed of 40, km/h can be | vedclass

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Question

(a) $S \propto {u^2}$

$	herefore \frac{{{S_1}}}{{{S_2}}} = {\left( {\frac{{{u_1}}}{{{u_2}}}} ight)^2}$

$&rArr;$ $\frac{2}{{{S_2}}} = \frac{1}

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(a) $S \propto {u^2}$

$	herefore \frac{{{S_1}}}{{{S_2}}} = {\left( {\frac{{{u_1}}}{{{u_2}}}} ight)^2}$

$&rArr;$ $\frac{2}{{{S_2}}} = \frac{1}{4} \Rightarrow {S_2} = 8\;m$

A car moving with a speed of $40\, km/h$ can be stopped by applying brakes after atleast $2\, m$. If the same car is moving with a speed of $80 \,km/h$, what is the minimum stopping distance............$m$

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