A car starts from rest and moves along the $x-$ axis with constant acceleration $5\, ms^{-2}$ for $8\,\sec $. If it then continues with constant velocity, what distance will the car cover in $12\,\sec $ since it started from the rest ?
A car starts from rest and moves along the $x-$ axis with constant acceleration $5\, ms^{-2}$ for $8\,\sec $. If it then continues with constant velocity, what distance will the car cover in $12\,\sec $ since it started from the rest ?
The distance travelled in first $8 \,s ,\,\, x_{1}=0+\frac{1}{2}(5)(8)^{2}=160\, m$
At this point the velocity $v=u+a t=0+(5 \times 8)=40 \,m s^{-1}$
Therefore, the distance covered in last four seconds, $x _{2}=(40 \times 4)\, m =160\, m$
Thus, the total distance $x=x_{1}+x_{2}=(160+160) \,m =320\, m$
Similar Questions
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$(a)$ Differentiate between distance and displacement.
$(b)$ Under what conditions is the magnitude of average velocity of an object equal to its average speed ?
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$(b)$ Under what conditions is the magnitude of average velocity of an object equal to its average speed ?
Study the given graph and answer the following questions
$(i)$ Which part of the graph shows accelerated motion ?
$(ii)$ Which part of the graph shows retarded motion ?
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$(ii)$ Which part of the graph shows retarded motion ?
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Time $(s)$
$0$
$10$
$20$
$30$
$40$
$50$
Speed $\left(m s^{-1}\right)$
$5$
$10$
$15$
$20$
$25$
$30$
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| Time $(s)$ | $0$ | $10$ | $20$ | $30$ | $40$ | $50$ |
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$(c)$ Draw velocity$-$time graph for uniform motion along a straight line. How can you find distance covered by a body from this graph ?