- Home
- Standard 11
- Physics
11.Thermodynamics
normal
A carnot engine working between $400\, K$ and $800 \,K$ has a work output of $1200\, J$ per cycle. What is the amount of heat energy supplied to the engine from source per cycle .... $J$ ?
A
$1200$
B
$1350$
C
$2400$
D
$2500$
Solution
$\mathrm{W}=1200 \mathrm{J}, \mathrm{T}_{1}=800 \mathrm{K}, \quad \mathrm{T}_{2}=400 \mathrm{K}$
$\therefore \quad \eta=1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=\frac{\mathrm{W}}{\mathrm{Q}_{1}} \Rightarrow 1-\frac{400}{800}=\frac{1200}{\mathrm{Q}_{1}}$
$\Rightarrow \quad 0.5=\frac{1200}{\mathrm{Q}_{1}}$
Heat energy supplied by source
$\mathrm{Q}_{1}=\frac{1200}{0.5}=2400$ joule per cycle
Standard 11
Physics