Gujarati
Hindi
11.Thermodynamics
normal

A carnot engine working between $400\, K$ and $800 \,K$ has a work output of $1200\, J$ per cycle. What is the amount of heat energy supplied to the engine from source per  cycle   .... $J$ ?

A

$1200$

B

$1350$

C

$2400$

D

$2500$

Solution

$\mathrm{W}=1200 \mathrm{J}, \mathrm{T}_{1}=800 \mathrm{K}, \quad \mathrm{T}_{2}=400 \mathrm{K}$

$\therefore \quad \eta=1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=\frac{\mathrm{W}}{\mathrm{Q}_{1}} \Rightarrow 1-\frac{400}{800}=\frac{1200}{\mathrm{Q}_{1}}$

$\Rightarrow \quad 0.5=\frac{1200}{\mathrm{Q}_{1}}$

Heat energy supplied by source

$\mathrm{Q}_{1}=\frac{1200}{0.5}=2400$ joule per cycle

Standard 11
Physics

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